(4x^-3y^0/2x^4y^-1)^(-2)

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Solution for (4x^-3y^0/2x^4y^-1)^(-2) equation:


D( x )

x = 0

((4*y^0*x^-3)/2)*x^4*y^-1 = 0

x = 0

x = 0

((4*y^0*x^-3)/2)*x^4*y^-1 = 0

((4*y^0*x^-3)/2)*x^4*y^-1 = 0

((4*x^-3)/2)*x^4*y^-1 = 0

2*x*y^-1 = 0 // : 2*y^-1

x = 0

x in (-oo:0) U (0:+oo)

(((4*y^0*x^-3)/2)*x^4*y^-1)^-2 = 0

(((4*x^-3)/2)*x^4*y^-1)^-2 = 0

1/4*x^-2*y^2 = 0 // : 1/4*y^2

x^-2 = 0

x naleu017Cy do O

x belongs to the empty set

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